Let $(1 + x + x^2)^{20}(2x + 1) = a_0 + a_1x^1 + a_2x^2 + ... + a_{41}x^{41}$,then $\frac{a_0}{1} + \frac{a_1}{2} + .... + \frac{a_{41}}{42}$ is equal to

  • A
    $\frac{2^{21} - 1}{21}$
  • B
    $\frac{3^{21} - 1}{21}$
  • C
    $\frac{2^{20} - 1}{20}$
  • D
    $\frac{3^{20} - 1}{20}$

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